The work done in rotating a dipole placed parallel to the electric field through 180^{\circ} is W. So, the work done in rotating it through 60^{\circ} is (\cos 0^{\circ}=1, \cos 60^{\circ}=\frac{1}{2}, \cos 180^{\circ}=-1)

MHTCET 13 May 2023 Shift 2 Solved Paper

Section: Physics

Question : 109 of 150

Marks: +1, -0

The work done in rotating a dipole placed parallel to the electric field through 180∘ is W. So, the work done in rotating it through 60∘ is (cos‌0∘=1,cos‌60∘=‌

,cos‌180∘=−1)

4W
3W
W∕2
W∕4

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