The equation of the line passing through the point (-1,3,-2) and perpendicular to each of the lines \frac{x}{1}=\frac{y}{2}=\frac{z}{3} and \frac{x+2}{-3}=\frac{y-1}{2}=\frac{z+1}{5} is

Correct Answer is : x+12=y−3−7=z+24

\frac{x+1}{2}=\frac{y-3}{7}=\frac{z+2}{4}

\frac{x+1}{2}=\frac{y-3}{-7}=\frac{z+2}{4}

\frac{x-1}{2}=\frac{y+3}{-7}=\frac{z+2}{4}

\frac{x-1}{2}=\frac{y+3}{7}=\frac{z-2}{4}

MHTCET 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 85 of 150

Marks: +1, -0

The equation of the line passing through the point (−1,3,−2) and perpendicular to each of the lines ‌

=‌

and ‌

x+2

−3

=‌

y−1

=‌

z+1

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