If {\I}=\int {2 x-7}/{\sqrt{3 x-2}} {\d} x, then {\I} is given by

Correct Answer is : 427(3x−2)32−349(3x−2)12+c, where c is a constant of integration.

\frac{106}{27}(3 x-2)^{\frac{3}{2}}+ {\c}, where {\c} is a constant of integration.

\frac{98}{27}(3 x-2)^{\frac{3}{2}}+ {\c}, where {\c} is a constant of integration.

\frac{4}{27}(3 x-2)^{\frac{3}{2}}-\frac{34}{9}(3 x-2)^{\frac{1}{2}}+ {\c}, where {\c} is a constant of integration.

\frac{4}{27}(3 x-2)^{\frac{3}{2}}+\frac{34}{9}(3 x-2)^{\frac{1}{2}}+ {\c}, where {\c} is a constant of integration

MHTCET 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 55 of 150

Marks: +1, -0

If I=∫‌

2x−7

√3x−2

dx, then I is given by

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