Halley's Comet revolves around the sun with time period of 76 years. The aphelion distance if perihelion is given by 8.9 \times 10^{10} {m}, will be (Take, mass of sun =2 \times 10^{30} {kg} and G=6.67 \times 10^{-11} {Nm}^{3} \/ {kg}^{2} )

MHT CET 2021 Physics Solved Paper

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Halley's Comet revolves around the sun with time period of 76 years. The aphelion distance if perihelion is given by 8.9×1010m, will be (Take, mass of sun =2×1030kg and G=6.67×10−11Nm3∕kg2 )

4.7×1011m
3.23×1012m
5.3×1012m
7.63×1011m

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