The potential at a point x (measured in \mu {m} ) due to some charges situated on the X-axis is given by v(x)=\frac{20}{(x^{2}-4)} V The electric field E at x=4 \mu {m} is given by

Correct Answer is : 109V∕um and in the + ve x-direction

\frac{5}{2} {V} \/ \mu {m} and in the - ve x-direction

\frac{5}{2} {V} \/ \mu {m} and in the + ve x-direction

\frac{10}{9} {V} \/ \mu {m} and in the - ve x-direction

\frac{10}{9} {V} \/ {um} and in the + ve x-direction

MHT CET 2021 Physics Solved Paper

Question : 33 of 100

Marks: +1, -0

The potential at a point x (measured in µm ) due to some charges situated on the X-axis is given by v(x)=‌

(x2−4)

V
The electric field E at x=4µm is given by

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