MHT CET 2021 Math Solved Paper

The general equation of an parabola having vertex at the origin and axis along positive Y-axis is
x2=4ay. . . (i)
On differentiating Eq. (i), we get
2x=4a‌

dy

dx

⇒‌‌‌

dy

dx

=‌

x

2a

⇒2a=‌

x

dy∕dx

Putting value of 2a in Eq. (i), we get
x2=2(‌

x

dy∕dx

)y⇒x‌

dy

dx

=2y