What is the relation between {d[ {H}_{2}]}/{d t} and {d[ {NH}_{3}]}/{d t} ?

Correct Answer is : d[NH3]dt=−23d[H2]dt

\frac{1}{2} {d[ {NH}_{3}]}/{d t}= {d[ {H}_{2}]}/{d t}

{d[ {NH}_{3}]}/{d t}=-\frac{2}{3} {d[ {H}_{2}]}/{d t}

\frac{2}{3} {d[ {NH}_{3}]}/{d t}= {d[ {H}_{2}]}/{d t}

{d[ {NH}_{3}]}/{d t}= {d[ {H}_{2}]}/{d t}

MHT CET 2021 Chemistry Solved Paper

Question : 88 of 100

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What is the relation between ‌

d[H2]

and ‌

d[NH3]

dt?

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