What is enthalpy of formation of {NH}_{3}, if bond enthalpies as ( {N} \equiv {N})=-941 {kJ} \/ {mol}, ( {H}- {H})=436 {kJ} \/ {mol} and ( {N}- {H})=389 {kJ} \/ {mol} ?

Correct Answer is : −42.5kJ∕mol

MHT CET 2021 Chemistry Solved Paper

Question : 12 of 100

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What is enthalpy of formation of NH3, if bond enthalpies as (N≡N)=−941kJ∕mol, (H−H)=436kJ∕mol and (N−H)=389kJ∕mol ?

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