If \sqrt{A^{2}+B^{2}} represents the magnitude of resultant of two vectors (A^{\to}+B^{\to}) and (A^{\to}-B^{\to}), then the angle between two vectors is

Correct Answer is : cos−1[−(A2−B2)2(A2−B2)]

\cos^{-1}[{2(A^{2}-B^2)}/({A^2+B^2})]

\cos^{-1}[{-{A^{2}-B^{2}}/{A^{2}B^{2}}]

\cos^{-1}[-{{(A^{2}-B^{2}})/{2(A^{2}-B^{2})}}]

\cos^{-1}[-{{(A^{2}-B^{2}})/{A^{2}+B^{2}}]

MHT CET 2019 Physics Solved Paper

Question : 33 of 50

Marks: +1, -0

If √A2+B2 represents the magnitude of resultant of two vectors (

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) and (

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), then the angle between two vectors is

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