MHT CET 2019 Math Solved Paper

Given curves are y=2x−x2 & y=x
From the above equations we get,
x=2x−x2
⇒x2−x=0
⇒x(x−1)=0⇒x=0,1
⇒y=0,1(respectively)
∴ intersecting points of the two curves are (0 ,0) and (1 ,1) ∴ required area =

1

∫

0

(2x−x2)dx−

1

∫

0

x.dx
=[

2x2

2

−

x3

3

]01−[

x2

2

]01
=[1−

1

3

]−[

1

2

]
=

2

3

−

1

2

=

1

6

sq.units