If A = [\table1,2,3;-1,1,2;1,2,4] then (\A^2-5A)\A^{-1} =

Correct Answer is : [−423−1−4212−1]

MHT CET 2018 Math Solved Paper

Question : 9 of 50

Marks: +1, -0

If A = [

] then (A2−5A)A−1 =

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