MHT CET 2018 Math Solved Paper

(c) x2−y2 + x + 3y - 2 = 0
Comparing the above equation with
ax2 + 2hxy + by2 + 2gx + 2fy + c = 0
we get
a = 1 ,h = 0 ,b = -1, g =

1

2

, f =

3

2

,c = -2
∴ req. point of intersection is:
(

hf−bg

ab−h2

,

gh−af

ab−h2

)
= (

0+ 1 2

−1

,

0− 3 2

−1

) ≡ (−

1

2

,

3

2

)