MHT CET 2018 Math Solved Paper

(d) A coin is tossed 3 times.
∴ possibilities are
HHH → X = 3 - 0 = 3
TTT → X = 3 - 0 = 3
HHT → X = 2 -1 = 1
HTH → X = 2-1 = 1
THH → X = 2 -1 = 1
HTT → X = 2 - 1 = 1
TTH → X = 2 -1 = 1
THT → X = 2 -1 = 1
∴ P ( X = 1) =

6

8

=

3

4