MHT CET 2017 Math Solved Paper

(b) Given, x dy+ 2y dx = 0

dy

dy

+

2dx

x

=0
After integrating on both sides, we get
∫

1

y

dy + 2 ∫

1

x

dx = log C
⇒ log y+2 log x = log C
⇒ yx2 = C
If x = 2 then y = 1,
So, C = 1 x 22 = 4
Hence, particular solution will be x2y = 4.