MHT CET 2017 Math Solved Paper

(c) Suppose X be a random variable which denotes the no. of heads in tossing a coin three times. X can take value 0,1,2,3.
As, y = ₹2x. So, Y can take the values ₹0, ₹2, ₹4 and ₹6
∴ P(y = 0) = P (0 head) =

1

8

P(y = 2) = P (1 head) =

3

8

P(y = 4) = P (2 heads) =

3

8

P(y = 6) = P (3 heads) =

1

8

Hence, expected gain
0(

1

8

) + 2(

3

8

) + 4(

1

8

) + 6(

1

8

)
=

6+12+6

8

= 3