The horizontal component of earth's magnetic field at a place is 0.4 \times 10^{4} {T}. If the angle of dip is 45^{\circ} the value of total intensity of earth's magnetic field is

Correct Answer is : 0.5×10−4T

Manipal Entrance Test 2020 Physics Paper

Question : 27 of 50

Marks: +1, -0

The horizontal component of earth's magnetic field at a place is 0.4×104T. If the angle of dip is 45∘ the value of total intensity of earth's magnetic field is

0.5×10−4T
0.4×10−4T
0.5×10−6T
0.4×10−6T

Validate

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