Manipal Entrance Test 2020 Physics Paper

The electric field,
E=‌

1

4πε0

⋅‌

q

r2

So, EA=‌

9×109×10×10−9×4

25×2

=7.2NC−1 along OD
=14.4NC−1 along OB
EC=‌

9×109×10×10−9×4

25×2

=7.2 along OC
=14.4 along OA
Resultant of EA and ED,E1=(14.4−7.2)
=7.2NC−1 along OA.
Resultant of EB and EC,E2=(14.4−7.2)
=7.2NC−1 along OB
Since, E1 and E2 are perpendicular to each other.
∴E=√E12+E22 is along 45∘ to OA upward.