Manipal Entrance Test 2019 Math Paper

Given that 3 cos x + 4 sin x = 6
Since the maximum value of (3‌cos‌x+4‌sin‌x)=+√32+42=5,
Hence there is no ′x′ satisfying 3‌cos‌x+4‌sin‌x=6
∴ No solution, as |sin‌x|≤1,|cos‌x|≤1 and both of them do not attain their maximum value for the same angle.