A perpendicular is drawn from the point P(2,4,-1) to the line \frac{x+5}{1}= \frac{y+3}{4}= \frac{z-6}{-9}. The equation of the perpendicular from P to the given line is

Correct Answer is : x−26=y−43=z+12

\frac{x-2}{6}=\frac{y-4}{3}=\frac{z+1}{2}

\frac{x+2}{6}=\frac{y-4}{3}=\frac{z+1}{2}

\frac{x+2}{-6}=\frac{y-4}{3}=\frac{z+1}{2}

\frac{x+2}{6}=\frac{y+4}{3}=\frac{z+1}{2}

Manipal Entrance Test 2019 Math Paper

Question : 53 of 70

Marks: +1, -0

A perpendicular is drawn from the point P(2,4,−1) to the line

x+5

y+3

z−6

−9

. The equation of the perpendicular from P to the given line is

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