Let \\omega is an imaginary cube roots of unity, then the value of 2(1+\\omega) (1+\\omega^{2} ) +3(2\\omega+1) (2 \\omega^{2}+1 )+...+(n+1)(n \\omega+1) (n\\omega^{2}+1 ) is

Correct Answer is : [n(n+1)2]2+n

Manipal Entrance Test 2019 Math Paper

Question : 27 of 70

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Let ω is an imaginary cube roots of unity, then the value of 2(1+ω)(1+ω2) +3(2ω+1)(2ω2+1)+...+(n+1)(nω+1)(nω2+1) is

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