Manipal Entrance Test 2019 Chemistry Paper

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Question : 50 of 50

Marks: +1, -0

In the oxidation of C6H5−CH2→CH3 by KMnO4 the product formed is

C6H5−CH2−CHO
C6H5−CH2−COOH
C6H6−COOH
C6H5−CH2−OH

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