Manipal Entrance Test 2018 Physics Paper

Applying Kirchhoffs law in the given figure.
At junction A
i+i1+i2=1...(i)
For loop (1)
−60i+(15+5)i1=0
⇒i1=3i...(ii)
For loop (2)
−(15+5)i1+10i2=0
⇒i2=2i1=6i...(iii)
On solving Eqs. (i), (ii) and (iii), we get
i=0.1A