The surface area of a black body is 5\times 10^{-4} {m}^{2} and its temperature is 727^\circ {\C}. The energy radiated by it per minute is (\\sigma=5.67 \times 10^{-8} {\J} \/ {\m}^{2}- {s}- {K}^{4} )

Manipal Entrance Test 2017 Physics Paper

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The surface area of a black body is 5×10−4m2 and its temperature is 727°C. The energy radiated by it per minute is (σ=5.67×10−8J∕m2−s−K4)

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