Manipal Entrance Test 2016 Math Paper

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Question : 30 of 70

Marks: +1, -0

The solution of the differential equation

dy

dx

=sin(x+y)‌tan(x+y)−1 is

cosec(x+y)+tan(x+y)=x+C
x+cosec(x+y)=C
x+tan(x+y)=C
x+sec(x+y)=C

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