Manipal Entrance Test 2015 Physics Paper

Block of mass m2 shoots off carrying some kinetic energy away from the system. To find its speed, potential energy of spring = maximum kinetic energy of blocks.

kd2

2

=(m1+m2)

v2

2

[k = force constant of spring]
v2=

kd2

m1+m2

with m1 along on the spring.
Maximum potential energy = Maximum kinetic energy of m2
⇒

1

2

kA2=

1

2

m1v2
⇒kA2=

km1d2

m1+m2

⇒A=d√

m1

m1+m2