What is the cell potential (standard emf, E° ) for the reaction below? [E^\circ( {Fe}^{2+}(a q) {Fe} )=0.44 V and E^\circ{H}^{-} )=+0.4 {V} ] 2 {Fe}(s)+ {O}_{2}(g)+2 {H}_{2} {O}(l) ⇋2 {Fe}^{2+}(a q)+4 {OH}^{-}(aq)

Correct Answer is : E°cell=+0.84V

Manipal Entrance Test 2014 Chemistry Paper

Question : 42 of 60

Marks: +1, -0

What is the cell potential (standard emf, E° ) for the reaction below?
[E°( Fe2+(aq)Fe)=0.44V and E°H−)=+0.4V]
2Fe(s)+O2(g)+2H2O(l)⇋2Fe2+(aq)+4OH−(aq)

E°cell=−0.48V
E°cell=−0.04V
E°cell=+0.84V
E°cell=+1.28V

Validate

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