Manipal Entrance Test 2013 Physics Paper

At a certain velocity of projection the body will go out of the gravitational field of the earth and will never return to the earth, this velocity is known as escape velocity.
ve=√

2GMe

Re

Given, Me=Mp,Rp=

Re

4

∴

vρ

ve

=√

Me

Me

×

Re

Re∕4

=√4=2
⇒ vp=2ve=2×11.2
=22.4‌km∕s