The slope of the tangent at (x, y) to a curve passing through (1, \frac{\\pi}{4} ) is given by \frac{y}{x}-\cos ^{2} ( \frac{y}{x} )then the equation of the curve is

Correct Answer is : y=x tan−1(logcx)

y=\tan ^{-1} (\log \frac{c}{x} )

y=x \tan ^{-1} (\log \frac{x}{c} )

y=x \tan ^{-1} (\log \frac{c}{x} )

Manipal Entrance Test 2013 Math Paper

Question : 64 of 80

Marks: +1, -0

The slope of the tangent at (x,y) to a curve passing through (1,

) is given by

−cos2(

)then the equation of the curve is

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