Manipal Entrance Test 2013 Chemistry Paper

IPCl5 No. of e− pairs around central atom P=5
No of lone pairs =0 and hybridisation-sp 3d Shape = trigonal bipyramidal. In PCl4+− number. of e− pairs =4, lone pairs =0, hybridisation =sp3 and shape − tetrahedral
In PCl6−− number of e− pairs =6, lone pairs =0 hybridisation =sp3d2 and shape is octahedral