_{7}^{14} {\N}+ _{0}^{1} n\to _{6}^{14} {\C}+ _{1}^{1} {H} is written as

Correct Answer is : 714N(n,p)614C

{ }_{7}^{14} {\N}(n, e) {_1^{1} {H}}

{ }_{7}^{14} {\N}(p,n ) {_6^{14} {C}}

_{7}^{14} {\N}( n,p ) {_6^{14} {C}}

{ }_{14}^{6} {\C}(p,n) {_14^{7} {N}}

Manipal Entrance Test 2013 Chemistry Paper

Question : 17 of 60

Marks: +1, -0

714N+01n→614C+11H is written as

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