Manipal Entrance Test 2013 Chemistry Paper
© examsiri.com
Question : 15 of 60
Marks:
+1,
-0
Calculate second electron affinity of oxygen for the process,
O − ( g ) + e − ( g ) → O 2 − ( g )
by using the following data
(i) Heat of sublimation of
Mg(s) = +147.7 k J mol− 1
(ii) Ionisation energy of Mg(g) to form
Mg2 + (g) = +2189.0 k J mol− 1
(iii) Bond dissociation energy for
O 2 = +498.4 kJ mol− 1
(iv) First electron affinity of
O(g) = -141.0 kJ mol− 1
(v) Heat formation of
MgO =-601.7 kJ mol− 1
(vi) Lattice energy of
MgO =-3791.0 kJ mol− 1
by using the following data
(i) Heat of sublimation of
Mg(s) = +147.7 k J mol
(ii) Ionisation energy of Mg(g) to form
Mg
(iii) Bond dissociation energy for
(iv) First electron affinity of
O(g) = -141.0 kJ mol
(v) Heat formation of
MgO =-601.7 kJ mol
(vi) Lattice energy of
MgO =-3791.0 kJ mol
Go to Question: