Management Aptitude Test Sep 2020 Paper

Since, seven equal cubes are joined and made a cuboid.
So, length of cuboid $=7\times 5=35\mathit{c}\mathit{m}$
breadth of cuboid $=5\mathit{c}\mathit{m}$
and height of cuboid $=5\mathit{c}\mathit{m}$
Now, surface area of resulting cuboid $=2\left(\mathit{l}\mathit{b}+\mathit{b}\mathit{h}+\mathit{h}\mathit{l}\right)$
$=2\left(35\times 5+5\times 5+5\times 35\right)$
$=2\left(175+25+175\right)$
$=2\times 375$
$=750{\mathit{c}\mathit{m}}^3$