Management Aptitude Test Sep 2020 Paper

There are total of 10 persons of which ${\mathit{P}}_1$ is always selected and hence ${\mathit{P}}_4$ and ${\mathit{P}}_5$ are not be included in the arrangement.
Now, person left $=10-3=7$
(as ${\mathit{P}}_1$ is already selected and ${\mathit{P}}_4$ and ${\mathit{P}}_5$ are not selected)
$\therefore$ To select4 persons from 7 persons
total ways $={}^7{\mathit{C}}_4$
Also, these 5 persons can be arranged in $5!$ ways.
$\therefore$ Required ways of arrangement $={}^7{\mathit{C}}_4\times 5!$