Management Aptitude Test Sep 2020 Paper

Time from 8 am of a particular day to $1\mathit{p}\mathit{m}$ on the following day $=29\mathit{h}$
Now, the clock gains 10 min in $24\mathit{h}$, it means that 24 h 10 min of this clock is equal to $24\mathit{h}$ of the correct clock.
$\therefore 24+\frac{10}{60}=\frac{145}{6}\mathit{h}$ of this clock
$=24\mathit{h}$ of the correct clock.
$29\mathit{h}$ of this clock $=\frac{24}{145}\times 6\times 29$
$=28\mathit{h},48\mathit{m}\mathit{i}\mathit{n}$ of correct clock
It means that the clock is 12 min faster than the correct clock. Therefore, when clock indicates $1\mathit{p}\mathit{m}$, the correct time will be 48min past 12 .