Management Aptitude Test Sep 2013 Paper

(b) According to the question, 4 teams have to chosen from 8 players.
Now, ways for choosing 4 teams from 8 players = ${}_{}^8{\mathit{C}}_4^{}$
= $\frac{8\times 7\times 6\times 5}{4\times 3\times 2\times 1}$ = 70
Now, as there have to 2 players in each team, then possible number of ways are $\frac{70}{2!}=\frac{70}{2}$ = 35 ways