Management Aptitude Test Sep 2011 Paper

Question : 84 of 200

Marks: +1, -0

The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If height of the tower is 50 m, the height of the building is

${50√3}/3$ m
$16 2/3$ m
50 $√3$
None of these

Validate

Solution:

(2) Let AB be the tower and CD be the building.
In ΔABC,
tan 60° =

{AB}/{BC}

⇒ BC =

{AB}/{\tan 60°}

⇒ BC =

50/√3

Now, in ΔBCD,
tan 30° =

{CD}/{BC}

⇒ CD = tan 30° ⋅ BC
⇒ CD =

50/√3⋅1/√3

50/3=16 2/3

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