Management Aptitude Test Feb 2012 Paper

(3) In first figure → starting from letter A in clockwise direction
A$\stackrel{+2}{\to }$ C$\stackrel{+2}{\to }$ E$\stackrel{+2}{\to }$ G
and $\left(7^2+5^2\right)-\left(4^2+3^2\right)$= 49
(middle number)
In second figure → starting from letter I in clockwise direction
I $\stackrel{+2}{\to }$K $\stackrel{+2}{\to }$M$\stackrel{+2}{\to }$ O
and $\left(8^2+4^2\right)-\left(6^2+2^2\right)$= 40
In third figure → starting from letter Q in clockwise directions
Q$\stackrel{+2}{\to }$S$\stackrel{+2}{\to }$U$\stackrel{+2}{\to }$W
and $\left(5^2+1^2\right)-\left(4^2+2^2\right)$= 6
Hence, ? = S and 6