Management Aptitude Test Feb 2012 Paper

Question : 107 of 200

Marks: +1, -0

A man who can swim 48 m/min in still water swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 min, what is the speed of the current?

30 m/min
31 m /min
29 m/min
32 m /min

Validate

Solution:

(4) Let speed of the current be x km/h.
Then,

200/{48 - x}- 200/{48 + x}

= 10
⇒ 20 (48 + x - 48 + x) = (48 + x) (48 - x)
⇒ 20 x 2x = 2304 -

x^2

⇒

x^2

+ 40x - 2304 = 0
⇒ x = 32 m/min

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