Management Aptitude Test Dec 2019 Paper

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Question : 93 of 200

Marks: +1, -0

A, B

and

C

start a business with

₹ 12000 .

A's share is half the sum of the shares of

B

and

C

. The share of

B

is

2 / 3

of the sum of the shares of

A

and

C .

Then, the share of

C

is

₹ 3200
₹ 4800
₹ 4000
₹ 3000

Solution:

A+B+C =12000

....(i)

A={1}/{2} × (B+C)

⇒ B+C=2 A

By substituting the value of

B+C=2 A

in Eq. (i),
we get

3 A=12000 ⇒A=₹ 4000

Also,

B={2}/{3} × (A+C)

⇒A+C={3 B}/{2}

By substituting the value of

A+C={3 B}/{2}

in Eq. (i),
we get

{3 B}/{2}+B=12000

⇒{5 B}/{2}=12000

⇒B={12000 × 2}/{5}=₹ 4800

Share of

C=₹[12000-(4000+4800)]

=₹[12000-8800]=₹ 3200

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