Management Aptitude Test Dec 2019 Paper

Question : 87 of 200

Marks: +1, -0

\A, \B

and

\C

can do a work in 5 days, 10 days and 15 days respectively. They started together to do the work but after 2 days

\A

and

\B

left.

\C

did the remaining work in how many days?

Solution:

(A+B+C)'s 2 day's work

=2({1}/{5}+{1}/{10}+{1}/{15})

=2({11}/{30})={11}/{15}

Remaining work

=1-{11}/{15}={4}/{15}

So,

{4}/{15}

of the work is done by

\C

={4}/{15} ×15=4

days

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