Management Aptitude Test Dec 2019 Paper

The total number of ways of drawing 4 cards from a pack of 52 cards is ${}^{52}{\mathit{C}}_4$ ways.
Let $\mathit{E}$ be the event of drawing one card from each suit. There are 4 different suits of 13 cards each in the pack of 52 cards.
So, 4 cards each of a different suit can be chosen in ${}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1)$ ways.
$\therefore \mathit{P}\left(\mathit{E}\right)=\frac{\mathit{n}\left(\mathit{E}\right)}{\mathit{n}\left(\mathit{S}\right)}$ $=\frac{{}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1\times {}^{13}{\mathit{C}}_1}{{}^{52}{\mathit{C}}_4}$ $=\frac{2197}{20825}$