Management Aptitude Test Dec 2012 Paper

Question : 88 of 200

Marks: +1, -0

Shyam had three notebooks X, Y and Z Of these, X had 120 pages, Y had 10% more and Z had 10% less. If he tore out 5%, 10% and 15% of pages in X, Y and Z respectively, then what per cent of total pages did he tear out?

8%
15%
7%
None of these

Validate

Solution:

(a) Number of pages in notebook X =120
Number of pages in notebook Y =110% of 120 = 132
Number of pages in notebook Z = 90% of 120 = 108
Total number of pages in all the notebooks = 120 + 132 + 108 = 360
Number of pages torn by Shayam
innotebook X = 5% of 120 = 6
in notebook Y = 10% of 132 = 13.2
in notebook Z =15% of 108 = 16.2
Total number of pages torn = 6 + 13.2+ 16.2 = 35.4
∴ Required percentage =

35.4/360

x 100 =9.8%

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