Management Aptitude Test 2018 Paper

(d) Let the side of a square be 'a' unit.
Then, Area of the square, ${\mathit{A}}_1={\mathit{a}}^2$
If side is increased by 20%, then
${\mathit{A}}_1=\left(\frac{120\mathit{a}}{100}\right)\times \left(\frac{120\mathit{a}}{100}\right)$ = $\frac{144}{100}{\mathit{a}}^2$
Increase in area in percentage (k)
= $\frac{\frac{144}{100}{\mathit{a}}^2-{\mathit{a}}^2}{{\mathit{a}}^2}$ x 100%
= $\frac{44{\mathit{a}}^2}{\left(100\right){\mathit{a}}^2}$ x 100% = 44 %
Hence, k = 44%
Or
Using $\left(\mathit{m}+\mathit{n}+\frac{\mathit{m}\mathit{n}}{100}\%\right)$ = $\left(20+20+\frac{400}{100}\%\right)$
=(40+ 4) % = 44%