Management Aptitude Test 2018 Paper

Directions

(Q. Nos. 121- 125) Study the information below to answer these questions.

The adult population of a town in 1990, was 20440 people of which 53% were females while 60% were illiterates. Of these, the number above the age of 50 in that year was 17%. In the 2000 Census, it was found that adult population has reached 30760, 48% of them being females. Of the total adult population in 2000, 72% were below the age of 50 and total illiterates were 7000. Assume uniform pattern of age distribution amongst males and females.

Question : 121 of 200

Marks: +1, -0

If every adult female below the age of 50 was given a special annual allowance of ? 24000 in 1990, which was increased to ? 30000 by the year 2000, by what percentage has the quantum of this annual allowance increased / decreased from 1990 to 2000 ?

Validate

Solution:

(Q.Nos. 121-125)

Total population of the town in 1990 =20440
Total number of females in 1990
=

53/100

x 20440 = 10833.2
Total number of Illiterate population in 1990 =12264
Total number of literate population in 1990 = 8176
Total number of population above the age of 50 yr
=

17/100

x 20440 = 34743
Total number of population below the age of 50 yr= 16965.2
In 2000,
Total population of town = 30760
Total number of females = 147643
Total number of males = 15995.2
Total number of population below the age of 50 yr = 22147.2
Total number of Illiterate population = 7000
Total number of literate population = 23760
Total number of population above the age of 50 yr = 8612.8

for Above Question
(d) Adult females above the age of 50 yr in 1990
= 53% of 3474.8 = 1842
∴ Total allowance given to them in1990 = 1842 x 24000 = ₹ 44208000
Adult females above the age of 50 yr in 2000
= 48% of 8612.8 = 4134
∴ Total allowance given to them in 2000= 4134 x 30000 = ₹ 124020000
∴Required percentage
=

{124020000 - 44208000}/44208000

x 100
=

79812/44208

x 100 = 180%

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