Management Aptitude Test 2018 Paper

Question : 115 of 200

Marks: +1, -0

Two dices are thrown. Find the probability of getting an odd number on one dice and a multiple of three on the other.

$1/3$
$1/6$
$1/5$
$2/5$

Solution:

(b) Total possible outcome of a dice i.e. (1, 2, 3, 4, 5, 6) = 6
Total possible outcome of a dice when the number is odd i.e. 1, 3, 5 = 3
Total possible outcome of a dice when a number is multiple of 3 i.e. 3, 6 = 2
Hence, required probability =

2/6×3/6=1/6

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