Management Aptitude Test 2017 Paper

(c) 283.33 km
Let, the two trains meet at distance 'x' km from Delhi.
Distance covered by train A in 45 min
= 100 × $\frac{45}{60}$ =75 km
Suppose, train A and train B meet at point M.
∴ $\frac{75+\mathit{y}}{136}=\frac{\mathit{y}}{100}$
⇒ 7500 + 100y = 136y
⇒36 y = 7500
⇒ y = 208.33 km
∴ Required distance from Delhi = (75 + 208.33) km
= 283.33 km