Management Aptitude Test 2016 Paper

Question : 82 of 200

Marks: +1, -0

There are 5 different green dyes, 4 different blue dyes and 3 different red dyes. How many combinations of dyes can be chosen taking atleast , , one green and one blue dye?

3720
4523 ,
5214
None of these

Validate

Solution:

(a ) Given, Green dyes = 5
’ Blue dyes = 4
Red dyes = 3
Required number of ways =

(2^5-1)(2^4-1)2^3

\;\;\;\;\;\;\;\;\;\;\;=

(32-1) × (16-1) × 8

\;\;\;\;\;\;\;\;\;\;\;=

31 × 15 × 8 = 3720

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