Management Aptitude Test 2015 Paper

(c) Let the total population of seven villages be x,
∴ Then, population of village R in 2012
= 16% of x = $\frac{16}{100}\mathit{x}$
∴ Population of village R below poverty line in 2014
= $\frac{16}{100}\mathit{x}\times \frac{110}{100}\times \frac{51}{100}$
Similarly, population of village Z in 2012
= 11% of x = $\frac{11}{100}\mathit{x}$
∴ Population village Z below poverty line in 2014
= $\frac{11}{100}\mathit{x}\times \frac{95}{100}\times \frac{42}{100}$
∴ Required ratio
= $\frac{\frac{16}{100}\mathit{x}\times \frac{110}{100}\times \frac{51}{100}}{\frac{11}{100}\mathit{x}\times \frac{95}{100}\times \frac{42}{100}}$
= $\frac{89760}{43890}=\frac{2}{1}$
= 2 : 1 (approx).