Management Aptitude Test 2014 Paper

(a) Let Aditi pay for the article = ₹ x
She spent ₹ 110 on its repair, so its total cost = ₹ (x + 110)
Now, she sold it to Samir at a profit of 20%.
So, sale price = {x + 110) + (x + 110) $\times \frac{20}{100}$
= (x+110)+ $\frac{\left(\mathrm{x}+110\right)}{5}$
=$\frac{5\mathrm{x}+550+\mathrm{x}+110}{5}=\mathrm{₹}\left(\frac{6\mathrm{x}+660}{5}\right)$
Now, Samir sold it to Vikas at a loss of 10%.
So, sale price =$\left(\frac{6\mathrm{x}+660}{5}\right)-\frac{6\mathrm{x}+660}{5}\times \frac{10}{100}$
= $\left(\frac{6\mathrm{x}+660}{5}\right)-\frac{6\mathrm{x}+660}{50}$
= $\frac{6\mathrm{x}+6600-6\mathrm{x}-660}{50}$
= ₹ $\frac{54\mathrm{x}+5940}{50}$
Now, finally Vikas sold it for ₹ 1188, at a profit of 10%
So, sale price = $\frac{54\mathrm{x}+5940}{50}$ + $\frac{54\mathrm{x}+5940}{50}\times \frac{10}{100}$
⇒ 1188 = $\frac{54\mathrm{x}+5940}{50}$+$\frac{54\mathrm{x}+5940}{500}$
⇒1188= $\frac{540\mathrm{x}+59400+54\mathrm{x}+5940}{500}$
⇒$\frac{594\mathrm{x}+65340}{500}$ =1188
⇒ 148.5x + 16335 = 148500
⇒148.5x = 132165
⇒x = $\frac{12165}{148.5}$
⇒x = ₹ 890
So, Aditi bought the article for ₹ 890.