Madhya Pradesh Police Exam Model Paper 9

Using the question, the following path is followed by Mr. GaykwadFrom the above figure the triangle formed is a right-angled triangle
Therefore, by Pythagoras theorem
${\left(20\right)}^2+{\left(21\right)}^2={\mathit{x}}^2$
$400+441={\mathit{x}}^2$
$\sqrt{841}=\mathit{x}$
$\mathit{x}=29$
Therefore, Mr. Gaykwad is facing North-East direction now and is at a distance of 29 km from the initial position.
Hence, ‘29 km and North-East’ is the correct answer.